Consider a small fluid element of size δx × δy × δz at any point in a static mass of fluid as shown in Fig.1. Since the fluid is at rest, the element is in equilibrium under the various forces acting on it. The forces acting on the element are the pressure forces on its faces and the self-weight of the element.
Let ‘p’ be the pressure intensity at the midpoint O of the element. Then the pressure intensity on the left hand face of the element is
The pressure intensity on the right hand face of the element is
The corresponding pressure forces on the left hand and the right hand faces of the element are
and
respectively.
Fig. 1 Fluid Element with Forces Acting on it in a Static Mass of Fluid
Likewise the pressure intensities and the corresponding pressure forces on the other faces of the element may be obtained as shown in Fig. 1. Further if ‘w’ is the specific weight of the fluid then the weight of the element acting vertically downwards is (w δx δy δz). Since the element is in equilibrium under these forces, the algebraic sum of the forces acting on it in any direction must be zero. Thus considering the forces acting on the element along x,y and z axes the following equations are obtained
ΣFx = 0
or ΣFy = 0
or ΣFz = 0
Equations 1, 2 and 3 indicate that the pressure intensity p at any point in a static mass of fluid does not vary in x and y directions and it varies only in z direction. Hence the partial derivative in eq. 3 may be reduced to total (or exact) derivative as follows.In vector notation Eq. 4 may be expressed as
– grad p = wk = ρgk
where ‘k’ is unit vector parallel to z axis.
The minus sign (–) in the above equation signifies that the pressure decreases in the direction in which z increases i.e., in the upward direction.
Equation 4 is the basic differential equation representing the variation of pressure in a fluid at rest, which holds for both compressible and incompressible fluids. Equation 4 indicates that within a body of fluid at rest the pressure increases in the downward direction at the rate equivalent to the specific weight ‘w’ of the liquid. Further if dz = 0, then dp is also equal to zero; which means that the pressure remains constant over any horizontal plane in a fluid.